关于VS C++报错 const char* 类型的实参与char *类型的形参不兼容解决办法
问题来源错误原因解决方案问题来源
在学习写C++代码时候，去练习课本上课后习题时候的问题，根据自己Java学习的经历盲写了段代码。
题目：
假设某销售公司有一般员工、销售员工和销售经理。月工资的计算办法是：一般员工月薪=基本工资；销售员工月薪=基本工资+销售额*提成率；销售经理月薪=基本工资+职务工资+销售额*提成率。编写程序，定义一个表示一般员工的基类Employee，它包含三个表示员工基本信息的数据成员：编号number、姓名name和基本工资basicSalary。由Employee类派生销售员工Salesman类，Salesman类包含两个新数据成员：销售额sales和静态数据成员提成比例commrate。再由Salesman类派生表示销售经理的Salesmanager类。Salesmanager类包含新数据成员：岗位工资jobSalary。为这些类定义初始化数据的构造函数，以及输入数据input、计算工资pay和输出工资条print的成员函数。设公司员工的基本工资是2000元，销售经理的岗位工资是3000元，提成率=5/1000。在main函数中，输入若干个不同类型的员工信息测试你的类结构。
代码:
#include <iostream>using namespace std;class Employee{public:Employee(char Snumber[] = "\0", char Sname[] = "\0", double bSalary = 2000) //这里报错{strcpy_s(number, Snumber);strcpy_s(name, Sname);basicSalary = bSalary;}void input(){cout << "编号："; cin >> number;cout << "姓名："; cin >> name;}void print(){cout << "员工 ：" << name << "\t\t编号：" << number << "\t\t本月工资：" << basicSalary << endl;}protected:char number[5];char name[10];double basicSalary;};class Salesman : public Employee{public:Salesman(int sal = 0){sales = sal;}void input(){Employee::input();cout << "本月个人销售额：";cin >> sales;}void pay(){salary = basicSalary + sales * commrate;}void print(){pay();cout << "销售员 ：" << name << "\t\t编号：" << number << "\t\t本月工资：" << salary << endl;}protected:static double commrate;int sales;double salary;};double Salesman::commrate = 0.005;class Salesmanager : public Salesman{public:Salesmanager(double jSalary = 3000){jobSalary = jSalary;}void input(){Employee::input();cout << "本月部门销售额：";cin >> sales;}void pay(){salary = jobSalary + sales * commrate;}void print(){pay();cout << "销售经理 ：" << name << "\t\t编号：" << number << "\t\t本月工资：" << salary << endl;}private:double jobSalary;};int main(){cout << "基本员工\n";Employee emp1;emp1.input();emp1.print();cout << "销售员\n";Salesman emp2;emp2.input();emp2.print();cout << "销售经理\n";Salesmanager emp3;emp3.input();emp3.print();}
错误原因
不规范代码导致默认实参和形参类型不匹配
解决方案
方案一: 将结构体中定义的 char * 前面加上 "const"修饰, 按照提示将类型进行规范
#include <iostream>using namespace std;class Employee{public:Employee(const char Snumber[] = "\0",const char Sname[] = "\0", double bSalary = 2000){strcpy_s(number, Snumber);strcpy_s(name, Sname);basicSalary = bSalary;}void input(){cout << "编号："; cin >> number;cout << "姓名："; cin >> name;}void print(){cout << "员工 ：" << name << "\t\t编号：" << number << "\t\t本月工资：" << basicSalary << endl;}protected:char number[5];char name[10];double basicSalary;};class Salesman : public Employee{public:Salesman(int sal = 0){sales = sal;}void input(){Employee::input();cout << "本月个人销售额：";cin >> sales;}void pay(){salary = basicSalary + sales * commrate;}void print(){pay();cout << "销售员 ：" << name << "\t\t编号：" << number << "\t\t本月工资：" << salary << endl;}protected:static double commrate;int sales;double salary;};double Salesman::commrate = 0.005;class Salesmanager : public Salesman{public:Salesmanager(double jSalary = 3000){jobSalary = jSalary;}void input(){Employee::input();cout << "本月部门销售额：";cin >> sales;}void pay(){salary = jobSalary + sales * commrate;}void print(){pay();cout << "销售经理 ：" << name << "\t\t编号：" << number << "\t\t本月工资：" << salary << endl;}private:double jobSalary;};int main(){cout << "基本员工\n";Employee emp1;emp1.input();emp1.print();cout << "销售员\n";Salesman emp2;emp2.input();emp2.print();cout << "销售经理\n";Salesmanager emp3;emp3.input();emp3.print();}
方案二:右侧栏创建的项目上右击“项目名称”——>“属性”—>“C/C++”—>“语言”，将“符合模式”改为“否”即可。如下所示：
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