使用Jquery.flot插件时出现“例外被抛出且未被接住”

如下代码

function generationHtml(title,displayName,startTime,endTime,select_key,flag){

var placeholder="<div>"+title+"</div>";

...............

placeholder+="<div id="viewPerformance_div_select_int"><table id=“table”><input type='text' class='Wdate'/><div id="dropList">这里有很多多选下啦</div></table>";

placeholder+="<div class="p10"><div id='placeholder_'+flag+'></ div><div id='overview_'+flag+'></div></div></div>";可以将每个页面固定显示的id="table"放在viewPerformance_div_select_int的上面，但是不便于控制ewPerformance_div_select_int 整块东西的显示。

return placeholder;

}

function drawChart(data){

var flag=500;

jQuery.each(data.root,function(key,value){

flag++;

var placeholder=generationHtml(................,flag);

$("#viewPerformance_div_select_int").html(placeholder);

$("#viewPerformance_div_select_int").append(placeholder);

$(placeholder).appendTo("#viewPerformance_div_select_int");

红色的支持ie，不支持google

问题:是否能使用$("#viewPerformance_div_select_int").insertAfter(“#placeholer_”+flag);

为了能灵活控制viewPerformance_div_select_int的显示和隐藏，可以采用insertAfter，但还没测试过

});

flag=500;

var d=[];

var plotdata=d;

jQuery.each(data.root,function(key,value){

flag++;

var tempArr=[],tempObj={};

for(var i=0;i<value.length;i++){

d.push(value[i].collectDate,value[i].kpiVlaue);

tempObj["data"]=d;

tempObj["label"]=key;

plotdata.push({data:d,label:key});

}

draw(d,place_holder,over_view);

});

}

function draw(d,place_holder,over_view);{

place_holder.css({width:"500px",height:"200px"});

over_view.css..............

var plot=$.plot(placeholder,);

}

描述：

在google浏览器上