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2000字范文 > c语言编写一个程序计算某年某月有几天 c语言:输入某一年的第几天 计算并输出它是这

c语言编写一个程序计算某年某月有几天 c语言:输入某一年的第几天 计算并输出它是这

时间:2021-05-23 02:34:06

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c语言编写一个程序计算某年某月有几天 c语言:输入某一年的第几天 计算并输出它是这

满意答案

这个问题很简单,以下是我写的源代码,调试通过,你可以试试,写的很基础,应该能看懂,不懂追问!

#include

#include

void Monthday(int year,int yearDay,int *pMonth,int *pDay)

{

int dec ;

if((year%4 == 0 && year %100 != 0) || (year % 400 == 0) )//若是闰年

{

dec = 0;

}

else dec = 1;

if(yearDay >= 1 && yearDay <= 31 )

{

*pMonth = 1;

*pDay = yearDay;

}

else if(yearDay >= 32 && yearDay <= 60 - dec)

{

*pMonth = 2;

*pDay = yearDay - 31;

}

else if(yearDay >= 61- dec && yearDay <= 91- dec )

{

*pMonth = 3;

*pDay = yearDay - 60- dec;

}

else if(yearDay >= 92- dec && yearDay <= 121 - dec)

{

*pMonth = 4;

*pDay = yearDay - 91- dec;

}

else if(yearDay >= 122- dec && yearDay <= 152- dec )

{

*pMonth = 5;

*pDay = yearDay - 121- dec;

}

else if(yearDay >= 153- dec && yearDay <= 183- dec )

{

*pMonth = 6;

*pDay = yearDay - 152- dec;

}

else if(yearDay >= 184- dec && yearDay <= 214 - dec)

{

*pMonth = 7;

*pDay = yearDay - 183- dec;

}

else if(yearDay >= 215- dec && yearDay <= 245 - dec)

{

*pMonth = 8;

*pDay = yearDay - 214- dec;

}

else if(yearDay >= 246- dec && yearDay <= 275- dec )

{

*pMonth = 9;

*pDay = yearDay - 245- dec;

}

else if(yearDay >= 276- dec && yearDay <= 306- dec )

{

*pMonth = 10;

*pDay = yearDay - 275- dec;

}

else if(yearDay >= 307- dec && yearDay <= 336- dec )

{

*pMonth = 11;

*pDay = yearDay - 306- dec;

}

else if(yearDay >= 337- dec && yearDay <= 367- dec )

{

*pMonth = 12;

*pDay = yearDay - 336- dec;

}

}

int main()

{

int year,yearDay;

int *pMonth = new int(0);

int *pDay = new int(0);

printf("请输入 年,日:\n");

scanf("%d,%d",&year,&yearDay);

Monthday(year,yearDay,pMonth,pDay);

printf("month = %d , day = %d\n",*pMonth,*pDay);

return 0;

}

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c语言编写一个程序计算某年某月有几天 c语言:输入某一年的第几天 计算并输出它是这一年的第几月第几日 具体怎样编程...

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