[杂项项目]纯C语言实现控制台小游戏——数字拼图

一年前写的小游戏，当时感觉小有成就，现在发现缺陷真的很多。不禁感叹，当时为什么会用那么多goto呢。在这里真的建议大家不要用goto。只是现在懒得改了，毕竟是小程序。贴出来供大家参考。如果有时间后序再添加注释。如有问题欢迎评论。

#include <stdio.h>#include <stdlib.h>#include<math.h>#include <time.h>#define max 10int x, y, step, label = 0;typedef struct score {int steps, steps2;double times;char name[18];}score;score sco[max + 1];char ch, buff[3];bool flag, flag1 = false;clock_t start, finish;bool over(){system("cls");printf("\n\n\n\n\t\t\t您共用了 %d 步 ,耗时 %.3f 分钟\n", step, (double)(finish - start) / 40000);system("pause");system("cls");printf("\n\n\n\n\n\n\n\n\t******************* 您是否重新开始游戏 (Y/N) ? *******************\n\n");scanf("%s", buff);ch = buff[0];if (ch != 'n'&&ch != 'N') {return false;}else {printf("\n\n\n\n\t++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++\n");printf("\t+++++++++++++++++++++++++ 感谢您的使用 +++++++++++++++++++++++++\n", step);printf("\t++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++\n\n");system("pause");exit(0);}return true;}void rank(score sco[],int n) {int i, j;sco[0] = sco[n];for (i = 0; i < n; i++)if (sco[n].steps2>sco[i].steps2) {for (j = n; j > i; j--)sco[j] = sco[j - 1];sco[i] = sco[0];break;}for (j = i - 1; j > 0; j--)if (sco[i].steps2 == sco[j].steps2&&sco[i].steps < sco[j].steps)sco[0] = sco[i], sco[i] = sco[j], sco[j] = sco[0], i = j;else if (sco[i].steps2 == sco[j].steps2&&sco[i].steps == sco[j].steps)if (sco[i].times < sco[j].times)sco[0] = sco[i], sco[i] = sco[j], sco[j] = sco[0], i = j;}int check2(int *p, int n) {int i, j, flag2 = 0;for (i = 1; i < n*n - 1; i++) for (j = 0; j < i; j++) if (p[j] > p[i])flag2++;if (!flag2)return 0;else if (flag2 % 2 == 0)return 2;elsereturn 1;}bool check(int *p,int n) {int i;flag = true;for (i = 0; i<n*n - 1; i++)if (p[i] != i + 1)flag = false;if (flag) {flag1 = false;return false;}return true;}int operation(int *p,int n) {scanf("%s", buff);ch = buff[0];if (ch >= 'a'&&ch <= 'z')ch -= 32;switch (ch) {case 'A': if (y == n - 1) return 1;p[x*n + y] = p[x*n + y + 1];p[x*n + y + 1] = 0;y++;step++;return 1;case 'W': if (x == n - 1) return 1;p[x*n + y] = p[(x + 1)*n + y];p[(x + 1)*n + y] = 0;x++;step++;return 1;case 'D': if (y == 0) return 1;p[x*n + y] = p[x*n + y - 1];p[x*n + y - 1] = 0;y--;step++;return 1;case 'S': if (x == 0) return 1;p[x*n + y] = p[(x - 1)*n + y];p[(x - 1)*n + y] = 0;x--;step++;return 1;case 'R': return 2;case 'M': return 3;case 'Q': printf("\n\n\t********************* 您是否要离开游戏 (Y/N) ? *********************\n\n");scanf("%s", buff);ch = buff[0];if (ch == 'y' || ch == 'Y')return 4;elsereturn 1;default: return 1;}return 0;}void map(int *p, int n) {int i, j;system("cls");printf("\n\n\n");for (i = 0; i < n; i++){printf("\t");for (j = 0; j < n; j++){if (p[n*i + j] != 0)printf("%-4d", p[n*i + j]);elseprintf(" ");}printf("\n\n");}printf("\n\t按方向键移动卡片至无卡片的地方 W:上 S:下 A:左 D:右 M:返回菜单 R:换图 Q:退出\n\n");finish = clock();printf("\n\t\t\t\t步数: %d\t 使用时间: %.3f 分钟 \n\n", step, (double)(finish - start) / 40000);}void reset(int *p, int n) {int i, j, flag2;system("cls");do {for (i = 0; i < n*n - 1; i++) {do {flag2 = 1;p[i] = rand() % (n*n - 1) + 1;for (j = 0; j < i; j++)if (p[i] == p[j])flag2 = 0;} while (!flag2);}flag2 = check2(p, n);if (flag2 == 1) {flag2 = p[n*n - 2];p[n*n - 2] = p[n*n - 3];p[n*n - 3] = flag2;}} while (!flag2);p[n*n - 1] = 0;for (i = 0; i<n; i++)for (j = 0; j<n; j++)if (p[i*n + j] == 0){x = i;y = j;}}void help() {int i = 0;system("cls");printf("\n\n\n\n\t--------------------------------+ 基本操作 +--------------------------------\n\n");printf("\n\n\t按方向键移动卡片至无卡片的地方 W:上 S:下 A:左 D:右 M:返回菜单 R:换图 Q:退出\n\n");printf("\n\n\t---------------------------+ 浅悠悠（王骏）制作 +---------------------------\n\n");if (label == 0)printf("\n\n\t--------------------------+ 暂时没有任何游戏记录 +--------------------------\n\n");elsefor (i = 1; i <= label; i++)printf("\n\n\t 第%02d名：%-18s 步数：%-5d 阶数：%-5d 时间：%-6.3lf分钟\n\n",i, sco[i].name, sco[i].steps, sco[i].steps2, sco[i].times);printf("\n\n\t----------------------------+ 按任意键返回菜单 +----------------------------\n\n");system("pause");}void game() {int n, *p;int mark;do {system("cls");printf("\n\n\n\n\t------------------+ 请输入阶数（推荐3——20阶） +------------------\n\n");scanf("%d", &n);if (n > 1)p = (int*)calloc(n*n, sizeof(int));elseprintf("\t********************** 您输入有误，请重新输入 **********************\n\n"), system("pause");} while (n <= 1);next1:step = 0;start = clock();reset(p, n);next2:map(p, n);if (check(p, n) == false) {printf("\n\n\t=================+ 恭喜您完成游戏，请输入您的姓名 +=================\n\n");scanf("%s", sco[++label].name);sco[label].steps = step;sco[label].steps2 = n;sco[label].times = (double)(finish - start) / 40000;rank(sco, label);if (over() == false)return;}mark = operation(p, n);if (mark == 1)goto next2;else if (mark == 2)goto next1;else if (mark == 3)return;else if (mark == 4)if (over() == false)return;free(p);}int main(){srand((int)time(0));do {system("cls");printf("\t-------------+ 欢迎来到浅悠悠数字拼图，请选择您的操作 +-------------\n\n");printf("\t-----+ 1.开始游戏 +-----+ 2.帮助 +-----+ 0(或其他).退出 +-----\n\n");printf("\t++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++\n\n");scanf("%s", buff);ch = buff[0];switch (ch){case'1':game(); break;case'2':help(); break;case'0':exit(0);default:exit(0);}} while (ch != '0');return 0;}