给定二维数组a[4][4] 4行4列#include<stdio.h>const int i=4;const int y =4;int main() {int b;int c;int r = 0;int d =1;int e=0;int n=0;int u = 3;int a[i][y] = {{1,2,4,5},{6,7,8,9},{10,11,12,13},{14,15,16,17} };for (b = 0; b < i; b++) {printf("\n");for (c = 0; c < y; c++) {printf(" %d", a[b][c]);}}printf("\n");for (b = 0; b < i; ++b) {for(c=0;c<y;++c){if (b = c) {d += a[b][c];}}}for (b = 0; b < i; b++) {for (c = 0; c < y; ++c) {if (b + c == 3) {n += a[b][c];}if (b == 0||b==3) {e += a[b][c];}if (c==3||c==0) {r += a[b][c];}}}printf("矩阵外围元素之和:%d\n",e+r-37);重复相加和为37printf("主对角线元素之和:%d\n",d);printf("副对角线元素之和:%d",n);return 0;}
如何用二维数组输出一个矩形 并求矩形的外围元素之和 主对角线元素之和 副对角线元素之和
