后端开发|php教程
xhr,php,ajax-post-json-php
后端开发-php教程
如题，用js向php发送一个请求并加载响应到当前页面的时候，如何避免重写是覆盖当前页面；
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具体情况是这样的：
js：
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var navLst = {};var reqInfo = {};reqInfo[ eqNav] = true;reqInfo[ eqSin] = qtrfss; //more limt options would be addedvar reqSent= JSON.stringify(reqInfo);var xhr = null;if(window.XMLHttpRequest){ xhr = new XMLHttpRequest();}else{ xhr = ActiveXObject(Microsoft.XMLHttp);}xhr.open(POST, /themes/ticket/model/echoNav.php,true);xhr.onreadystatechange=function(){ if(xhr.readyState == 4) { if(xhr.status == 200) { try{var resp = eval((+ xhr.responseText +));listMenu(resp); }catch(e){listMenu(e); } } else { //undo } }};xhr.setRequestHeader(Content-Type, application/x-www-form-urlencoded);xhr.send( eqSent=+reqSent);
/themes/ticket/model/echoNav.php返回的是一个数组字符串化的json；
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然后获取到了menlist，重写的时候整个页面只剩下menulist了。。。
listmenu:
function listMenu(menuLst){
//var menuLst = [Sci-Fi,home,wiki];//menu lst should come from phpvar nav = \; var navIE = \+ \+ \+ \+ \+ \+ \+ \+ \+ \+ + \+ \;var navStyle = \;//stylesheets urlnav +=navIE;nav +=navStyle;nav +=\;document.write(nav);var navUl = document.createElement(ul); navUl.id = onav_bar;var navLst = \for (var i=0 ;i <= menuLst.length - 1; i++) { var navLi = document.createElement(li); var achor = document.createElement(a); if(i == 0){ navLi.className = onav_top onav_logo; achor.setAttribute(href,#); var spanX = document.createElement(span); spanX.className = onav_yellow; spanX.innerHTML = Sci-Fi; achor.appendChild(spanX); var spanY = document.createElement(span); spanY.className = onav_white; spanY.innerHTML = .Net; achor.appendChild(spanY); }else{ navLi.className = onav_top; achor.setAttribute(href,#); achor.setAttribute( arget,\_blank); achor.setAttribute( itle,menuLst[i]); achor.innerHTML = menuLst[i]; } navLi.appendChild(achor); navUl.appendChild(navLi);};var navDiv = document.getElementById(onav_wrapper); navDiv.appendChild(navUl);//need to be briefvar oAhor = document.getElementById(onav_bar).getElementsByTagName(a);for (i=0; i<oAhor.length; i++) { var testAttr = oAhor[i].parentNode.getAttribute(class); if (oAhor[i].href == window.location) { if (testAttr === null) { oAhor[i].parentNode.setAttribute(class, onav_active); } else{ oAhor[i].parentNode.setAttribute(class, testAttr + onav_active); } }}}
解决方案：
是document.write(nav);, DOM加载完成后再用document.write()方法会覆盖以前内容。测试一下，把其中函数中的方法换成document.write(\)
